SOLUTION: Suki is training in her wheelchair for the 100-meter race at the next Paralympics. In her initial acceleration phase, she averages a speed of 2.7 meters per second. At her maximum

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Suki is training in her wheelchair for the 100-meter race at the next Paralympics. In her initial acceleration phase, she averages a speed of 2.7 meters per second. At her maximum       Log On


   



Question 1014915: Suki is training in her wheelchair for the 100-meter race at the next Paralympics. In her initial acceleration phase, she averages a speed of 2.7 meters per second. At her maximum speed phase, she averages a speed of 6.6 meters per second. If she finishes a practice race in 18.1 seconds, how many meters long (to the nearest tenth of a meter) is her initial acceleration phase?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x= length of the acceleration phase, in meters.
100-x= length of the maximum speed phase, in meters.
At an average speed of %222.7+m+%2F+s%22 ,
Suki will cover the first x meters in
x%2F2.7 seconds.
Then, she will complete the remaining 100-xmeters,
at an average speed of %226.6+m+%2F+s%22 , in
%28100-x%29%2F6.6 seconds.
Since both stages add up to 18.1 seconds, our equation is
x%2F2.7%2B%28100-x%29%2F6.6=18.1 .

Solving:
x%2F2.7%2B%28100-x%29%2F6.6=18.1
Multiplying both sides of the equal sign times 2.7%2A6.6 , we get
6.6x%2B2.7%28100-x%29=18.1%2A2.7%2A6.6
6.6x%2B270-2.7x=322.452
6.6x-2.7x=322.452-270
3.9x=52.452
x=52.452%2F3.9=13.449(rounded to 3 decimal places).
So, to the nearest tenth of a meter, Suki's initial acceleration phase is highlight%2813.4%29 meters long.