SOLUTION: Find two consecutive odd integers such that their product is 95 more than 5 times their sum.

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Question 1014893: Find two consecutive odd integers such that their product is 95 more than 5 times their sum.
Answer by frcasem(2) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = be the first odd integer
x+ 2 = be the second odd integer
product of the integers: x(x+2)
sum of the integers: x+x+2 = 2x +2
Product of integers = 95 more than 5 times their sum
x(x + 2) = 5 (2x + 2) + 95, using distributive property
x^2+2x = 10x+10+95, combine similar terms and equate to 0
x^2 - 8x - 105 = 0, solve by factoring
(x - 15)(x+7) = 0
Using zero product property
x - 15 = 0; x = 15
x+ 7 = 0; x = -7
If x = 15, then x+2 = 17.
If x= -7 , then x+2 = -5