SOLUTION: y+1=x -2x+3y=2

 y + 1 = x     (1)
-2x + 3y = 2.  (2)

Probably, you want to solve this system although you do not say it directly and explicitly.

For it, substitute the expression x = y+1 from (1) into equation (2).
By doing so, you will exclude the unknown x and will get a single equation for the unknown y:

-2*(y+1) + 3y = 2,  or 

-2y - 2 + 3y = 2,   or

y = 2 + 2 = 4.

Hence, x = y + 1 = 5.