SOLUTION: Three consecutive even numbers are such that the sum of the first two is 20 more than the third. Find them.

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Question 1014718: Three consecutive even numbers are such that the sum of the first two is 20 more than the third. Find them.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be N-2,N, and N%2B2.
Then,
N-2%2BN=N%2B2%2B20
2N-2=N%2B22
N=24
So the numbers are 22,24, and 26.
.
.
Verifying,
22%2B24=26%2B20
46=46
True, good solution.