SOLUTION: Over a three week period, the price of an gram of gold increased by 25% in the first week, decreased by 20% in the following week, and increased by 5% in the third week. if the pri
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Question 1014697: Over a three week period, the price of an gram of gold increased by 25% in the first week, decreased by 20% in the following week, and increased by 5% in the third week. if the price of gold was G dollars per gram at the beginning of the three weeks, what was the price in terms of G at the end of the three weeks? Found 2 solutions by Theo, skippo:Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! g + .25g is equal to 1 * g + .25 * g which is equal to (1 + .25) * g which is equal to 1.25 * g which is equal to 1.25g.
1.25g - .2 * 1.25g is equal to 1 * 1.25 * g - .2 * 1.25 * g which is equal to (1 - .2) * 1.25 * g which is equal to .8 * 1.25 * g which is equal to 1 * g which is equal to g.
g + .05g is equal to 1 * g + .05 * g which is equal to (1 + .05) * g which is equal to 1.05 * g which is equal to 1.05g.
the value of the gold at the end of week 3 is equal to 1.05g.
You can put this solution on YOUR website! Over a three week period, the price of an gram of gold increased by 25% in the first week, decreased by 20% in the following week, and increased by 5% in the third week. if the price of gold was G dollars per gram at the beginning of the three weeks, what was the price in terms of G at the end of the three weeks?
solution:
amount = G
1st week: (25% increase) 25% of G = (25/100)x G
= G/4
increase = G+(G/4) = 5G/4
2nd week: (20% decrease) 20% of 5G/4 = (20/100)x 5G/4
= (1/5) x 5G/4
= G/4
decrease = (5G/4)-(G/4)
= (5G-G)/4
= G
3rd week: (5% increase) 5% of G = (5/100)x G
= G/20
increase = G+(G/20)
= 21G/20
