SOLUTION: The route from A to B passes two traffic light. at the first traffic light ,the red light lasts for 12 seconds,the green light for 25 seconds and yellow light for 3 seconds.at the
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Question 1014696: The route from A to B passes two traffic light. at the first traffic light ,the red light lasts for 12 seconds,the green light for 25 seconds and yellow light for 3 seconds.at the second traffic light,the red light lasts for 10 seconds, the green light for 8 seconds & yellow light for 2 seconds.
What is the probability of driving a car from A to B without waiting for the traffic lights? Answer by Theo(13342) (Show Source):
the probability of the first light being green is 25/40 because it is green for 25 seconds out of each cycle of 40 seconds.
the probability of the second light being green is 8/20 because it is green for 8 seconds out of each cycle of 20 second.
assuming that you have a random chance of hitting a green light each time you get to each light, then the probability of getting two greens in a row is 25/40 * 8/20 = 200 / 800 = 2/8 = 1/4.
you will be able to get through both lights without stopping 25% of the time.
