SOLUTION: Find Three consecutive odd integers such their sum decreased by the second equals 50

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Question 1014478: Find Three consecutive odd integers such their sum decreased by the second equals 50
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Think about the descripton a few seconds. n any integer, 2n+1 and 2n+5 are the first and third
of these consecutive odd integers and the description means,

%282n%2B1%29%2B%282n%2B5%29=50


Do the steps; find that n=11.
Evaluate the integers.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find Three consecutive odd integers such their sum decreased by the second equals 50 
Let the first integer be F

Then other 2 are: F + 2, and F + 4

We then get: F + F + 2 + F + 4 - (F + 2) = 50

Solve for F, the 1st integer, then F + 2, and F + 4, for the 2nd and 3rd, respectively

Hint: You should get F, or 1st integer as 23.