SOLUTION: 5.3 Solve the following exponential equation by expressing each side as a power of the same base and then equating exponents. 4^x+7 =16^x-4 The solution set is { } I go

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 5.3 Solve the following exponential equation by expressing each side as a power of the same base and then equating exponents. 4^x+7 =16^x-4 The solution set is { } I go      Log On


   



Question 1014354: 5.3
Solve the following exponential equation by expressing each side as a power of the same base and then equating exponents.
4^x+7 =16^x-4
The solution set is { }
I got 15. Is this correct?

Found 2 solutions by ikleyn, rothauserc:
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the following exponential equation by expressing each side as a power of the same base and then equating exponents.
4^x+7 =16^x-4
The solution set is { }
I got 15. Is this correct?
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This is correct.

Great job!

Your equation is 4%5E%28x%2B7%29 = 16%5E%28x-4%29.

Next time use parentheses when submit posts like this one.


Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
if your problem is 4^(x+7) = 16^(x-4), you are correct since
16^(x-4) = (4^2)^(x-4) = 4^(2x-8), then
4^(x+7) = 4^(2x-8)
x+7 = 2x-8
x = 15