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Question 1014246: find out the greater integer which is greater than three times of integer by adding 5 into its two times ( the answer is 6 but how??? please help in solving this question)
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! i'm not sure what you mean by adding 5 into it 2 times.
if the number is x and you add 5 into it 2 times, then the number will be x + 5 + 5 which is equal to x + 10.
your equation would be x + 10 > 3x
that says that you have a number and add 5 into it two times and the result is greater than 3 times the number.
you would solve this problem as follows:
start with x + 10 > 3x
subtract x from both sides of the equation to get 10 > 3x - x
simplify to get 10 > 2x
divide both sides of the equation by 2 to get 5 > x
if x is the greatest integer < 5, then x has to be equal to 4.
since x doesn't equal to 6, this can't be right.
for x to be equal to 6, the left side of your equation would have to be be > 18 because 3x = 18 when x = 6.
when x = 6, some of the possible combinations are:
2x + 5 = 2*6 + 5 = 17 which is not greater than 18.
2 * (x+5) = 2 * (6 + 5) = 2 * 11 = 22 which is greater than 18.
solving this last equation, i do the following:
start with 2 * (x+5) > 3x
distribute the multiplication to get 2x + 10 > 3x
subtract 2x from both sides of the equation to get 10 > x
the greatest integer that satisfies this equation is x = 9.
i'm struggling with what you mean by adding 5 into it 2 times.
this means to me that i take the number and add 5 into it 2 times.
if the number is x, then i would get x + 5 + 5 = x + 10, but that doesn't get you the answer you're looking for so something is wrong.
send me the problem exactly the way it is written and i'll see if i can make sense out of it.
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