SOLUTION: Find all real solutions of the equation. (Use any method) a. x^2 - 0.011x

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Question 1014213: Find all real solutions of the equation. (Use any method)
a. x^2 - 0.011x - 0.064 = 0
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
i used the quadratic formula because it didn't look like it could be factored easily, if at all.

quadratic formula is:

-b - sqrt(b^2-4ac) x = --------------------- 2a or: -b + sqrt(b^2-4ac) x = --------------------- 2a

your equation is in standard form ax^2 + bx + c = 0

a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the contant term.

your equation is x^2 - 0.011x - 0.064 = 0

that means that:

a = 1
b = -.011
c = .064

just replace the variables in the equation and solve for x.

you will get:

x = -.24754199.... or x = .25854199...

round as required.

you could also have graphed this equation using a graphing calculator and would have gotten the same answer.

here's the graph that i did.

SOLUTION: Find all real solutions of the equation. (Use any method) a. x^2 - 0.011x - 0.064 = 0