SOLUTION: Find two consecutive odd integers such that their product is 79 more than 8 times their sum.

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Question 1014158: Find two consecutive odd integers such that their product is 79 more than 8 times their sum.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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x and x+2 are consecutive odd integers
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%28x%29%28x%2B2%29=8%28x%2Bx%2B2%29%2B79
x%5E2%2B2x=8%282x%2B2%29%2B79
x%5E2%2B2x=16x%2B16%2B79
x%5E2%2B2x=16x%2B95
x%5E2-14x-95=0
%28x-19%29%28x%2B5%29=0
x-19=0 OR x%2B5=0
x=19 OR x=-5
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ANSWER: The integers are 19 and 21 or -5 and -3.
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CHECK:
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For 19 and 21:
%2819%29%2821%29=8%2819%2B21%29%2B79%0D%0A%7B%7B%7B399=8%2840%29%2B79
399=320%2B79
399=399
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For -5 and -3:
%28-5%29%28-3%29=8%28-5%2B%28-3%29%29%2B79
15=8%28-8%29%2B79
15=-64%2B79
15=15
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