You can put this solution on YOUR website!
First we'll try a sum of nth powers with the first two terms:
If that doesn't work, we'll try the difference of nth powers
No good. Comes out with imaginary values for x and y
So we try a difference of powers for the first two terms:
So the formula we get from the first two terms,
substituting x=3 and y=-2 in
becomes
But we must check to see if it holds for all the given
numbers in the series:
So it works for all the given terms, so the formula is:
Edwin
