SOLUTION: 4.1
Find the coordinates of the vertex for the parabola defined by the given quadratic function.
f(x) =-4(x+3)^2 +6
The vertex is: (type an ordered pair)
The answer I
Algebra ->
Functions
-> SOLUTION: 4.1
Find the coordinates of the vertex for the parabola defined by the given quadratic function.
f(x) =-4(x+3)^2 +6
The vertex is: (type an ordered pair)
The answer I
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Question 1013998: 4.1
Find the coordinates of the vertex for the parabola defined by the given quadratic function.
f(x) =-4(x+3)^2 +6
The vertex is: (type an ordered pair)
The answer I got was (-3,6) is this right? Found 3 solutions by Alan3354, Edwin McCravy, fractalier:Answer by Alan3354(69443) (Show Source):
When the quadratic function, f(x) is given as the equation of a
parabola in the form
f(x) = a(x-h)² + k
then the vertex of the parabola is (h,k)
Your function is
f(x) = -4(x+3)² + 6
So -h = +3 and h = -3 and k = 6, so the vertex is
(h,k) = (-3,6).
So you are correct.
Edwin
