SOLUTION: The following are from the Compass sample test.
Algebra Placement
Linear equations
15.What is the slope of the line with the equation 2x+3y+6=0
Please explain how to get to
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Polynomials-and-rational-expressions
-> SOLUTION: The following are from the Compass sample test.
Algebra Placement
Linear equations
15.What is the slope of the line with the equation 2x+3y+6=0
Please explain how to get to
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Question 101398: The following are from the Compass sample test.
Algebra Placement
Linear equations
15.What is the slope of the line with the equation 2x+3y+6=0
Please explain how to get to the answer of -2/3
16. Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?
Please explain how to get to the answer of (8,1)
To find the slope we need to convert this equation to the slope intercept form which is:
y=mx+b
m is the slope and b is y intercept.
2x + 3y + 6 = 0
first move 2x to the right side of the equation
This is done by subtracting 2x from both sides
2x - 2x + 3y + 6 = 0-2x
on the left side 2x-2x cancel out and on the right side 0-2x leaves -2x so we get this
3y + 6 = -2x
next move 6 following the same procedure
3y + 6 - 6 = -2x - 6
3y = -2x - 6
finally isolate y by dividing by 3 across the equation
Now that we have convert the equation to slope intercept form we can identify the slope, which is:
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16. Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?
For this one I would just plot the information given on a graph.
First plot point A at (-4,1) Then draw the line x=2 which is a vertical line that crosses the x axis at 2. Once we have done this we can see that point A is 6 units away from the the line x=2 so point B must be 6 units away on the x axis for line x=2 to be a bisector of line segement AB. Also point B must have the same x intercept as point A for line segment AB to be perpendicular to line x=2. The only point on the graph that meets these requirements is (8,1)