SOLUTION: Max can finish repairing a machine in 4 hours. His helper can do the same job in 8 hours. Max began the job alone and work for 2 hours.His helper joined until the was completed. Ho

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Max can finish repairing a machine in 4 hours. His helper can do the same job in 8 hours. Max began the job alone and work for 2 hours.His helper joined until the was completed. Ho      Log On


   



Question 1013758: Max can finish repairing a machine in 4 hours. His helper can do the same job in 8 hours. Max began the job alone and work for 2 hours.His helper joined until the was completed. How long did it take them to finish the job?

Found 2 solutions by josgarithmetic, Edwin McCravy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
4%2F3, hours

OR
1 hour 40 minutes.


--
Done with solution shown less than 10 minutes ago.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
That answer above 1 hour 40 minutes is incorrect, although the 4/3 hours
is correct.

Max can finish repairing a machine in 4 hours.
His helper can do the same job in 8 hours. Max began the job alone
and work for 2 hours.His helper joined until the was completed.
How long did it take them to finish the job?
Let the answer be x.  Make this chart and put x in the middle column
on the 4th row,

                            fraction
                               of
                              jobs     time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job         
Helper alone doing 1 job   
Max alone for 2 hours
Both together for x hours               x

Max can finish repairing a machine in 4 hours. 

So he can do 1 job in 4 hours so we fill in the first two blanks
in the first row:

                            fraction
                               of
                              jobs     time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4 
Helper alone doing 1 job   
Max alone for 2 hours
Both together for x hours               x



His helper can do the same job in 8 hours. 

So the helper can do 1 job in 8 hours so we fill in the first two blanks
in the second row:

                            fraction
                               of
                              jobs     time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4 
Helper alone doing 1 job       1        8  
Max alone for 2 hours
Both together for x hours               x
 
Next we fill in the rates in the first two rows by dividing the
jobs done by the time in hours.

                            fraction
                               of
                              jobs     time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4           1/4
Helper alone doing 1 job       1        8           1/8
Max alone for 2 hours                   
Both together for x hours               x

Max began the job alone and work for 2 hours.

Max's rate for those 2 hours is the same as when doing 1 job, 
namely 1/4, so we put 2 for the hours in the 3rd row and 1/4 for the rate 

                            fraction
                               of
                              jobs     time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4           1/4
Helper alone doing 1 job       1        8           1/8
Max alone for 2 hours                   2           1/4
Both together for x hours               x

We fill in the number of jobs done by multiplying the rate by
the time (1/4)(2) = 1/2, which is half a job, so we fill 1/2
in the 1st column on the 3rd row:

                            fraction
                               of
                              job      time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4           1/4
Helper alone doing 1 job       1        8           1/8
Max alone for 2 hours         1/2       2           1/4
Both together for x hours               x 

His helper joined until the was completed. 

Their combined rate is the sum of their rates, 1/4+1/8 = 2/8+1/8 = 3/8
So we fill that in the last column on the 4th row:

                            fraction
                               of
                              job      time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4           1/4
Helper alone doing 1 job       1        8           1/8
Max alone for 2 hours         1/2       2           1/4
Both together for x hours               x           3/8

We fill in the number of jobs done in the x hours by multiplying the 
rate by the time (3/8)x, so we fill 1/2 in the 1st column on the 4th row:

                            fraction
                               of
                              jobs     time      rate in
                              done    in hrs     jobs/hr
Max alone doing 1 job          1        4           1/4
Helper alone doing 1 job       1        8           1/8
Max alone for 2 hours         1/2       2           1/4
Both together for x hours   (3/8)x      x           3/8

How long did it take them to finish the job?

The sum of the fractions of a job done in the 2 hours plus the fraction
of the job done in the x hours must total up to 1 job, so

                       1/2 + (3/8)x = 1

Multiply through by LCD = 8

                          4 + 3x = 8
                              3x = 4
                               x = 4/3 = 1 1/3 hours = 1 hour 20 minutes

                               
Edwin