SOLUTION: Determine the number of real zeros of the function. F(x)=x^3+4x^2+x-6

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Determine the number of real zeros of the function. F(x)=x^3+4x^2+x-6       Log On


   

Question 1013736: Determine the number of real zeros of the function. F(x)=x^3+4x^2+x-6
Answer by ikleyn(52873) About Me  (Show Source):
You can put this solution on YOUR website!
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Check the divisors of the number 6, the constant term:
+/-1, +/-2, +/-3 and +/-6.