SOLUTION: An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 210 feet of antique picket fencing are to be used to enclose the garden

Algebra ->  Triangles -> SOLUTION: An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 210 feet of antique picket fencing are to be used to enclose the garden      Log On


   

Question 1013682: An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 210 feet of antique picket fencing are to be used to enclose the garden, find the dimensions of the garden.
Found 2 solutions by Boreal, reelmccray:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
L=x
W=2x/3
2L+2W=210=2x+4x/3
multiply everything by 3
630=6x+4x=10x
x=63
2/3x=42
they sum to 105, and double that, the perimeter, is 210.
The garden is 63 x 42 feet.

Answer by reelmccray(6) About Me  (Show Source):
You can put this solution on YOUR website!
P=Perimeter
W=Width
L=Length
Assuming the 210 feet is the perimeter
P = 210 feet
P = 2W + 2L
in this case W = 2/3 L . . . so sub W with 2/3 L in the equation
P = 2(2/3 L)+ 2(L) = 210 feet
4/3 L + 2L = 210 feet
10/3 L = 210 feet
Multiply both sides by 3/10 to solve for L
L = (210)(3/10) = 63 feet
W = 2/3 L so W = 2/3 x 63 = 42 feet
Garden is 42 feet wide by 63 feet long