Question 1013646: Hi
80% of the water in a bucket takes 4 hours to leak out through one hole.a second hole is made.assuming water leaks out of the holes at a constant rate, how long woul it take half the remaining water to leak out.
thanks
Found 3 solutions by Alan3354, Theo, josmiceli:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 80% of the water in a bucket takes 4 hours to leak out through one hole. a second hole is made. assuming water leaks out of the holes at a constant rate, how long would it take half the remaining water to leak out.
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Assuming the flow rates are the same for the 2 holes:
Each hole leaks 20% of the bucket per hour --> 40%/hr for the 2 holes.
20% of the bucket's contents remain.
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Half of the 20% = 10%
10%/40% = 1/4 hour
Answer by Theo(13342)  (Show Source):
You can put this solution on YOUR website! 80% of the bucket is drained in 4 hours.
this means the the bucket is being drained at a rate of 20% of the bucket each hour.
after 4 hours, there is 20% of the water in the bucket left.
at the same rate, half of that will be drained in a half an hour.
since there size of the hole in the bucket is doubled because another leak sprang up that was draining the bucket at the same rate as the first leak, then the rate of draining is doubled and half of the 20% will be drained in a quarter of an hour rather than a half hour.
if you work this problem using rate * time = quantity formula, you will get the following:
rate * time = quantity
rate is the speed as which the bucket is leaking.
time is the amount of time the bucket is leaking.
quantity is the amount of water in the bucket that is being drained.
80% = .8 * the capacity of the bucket.
time is 4 hours.
rate * time formula = rate * 4 = .8
solve for rate to get rate = .8/4 = .2
rate of .2 means that 20% of the bucket is being drained every hour.
so, you have:
rate = .2
time = 4
quantity = .8
.2 * 4 = .8 becomes .8 = .8, confirming the values are correct.
now:
80% of the bucket has been drained.
this leaves 20%.
half of that is 10%.
10% = .1
quantity remaining to be drained is .1 * capacity of the bucket.
the rate from one leak is 20% of the bucket being drained each hour.
another leak at the same rate will double this.
therefore, with two leaks, the rate at which the bucket is being drained is 40% of the bucket per hour.
40% = .4
your new rate is .4
your new quantity is .1
rate * time = quantity becomes .4 * time = .1
solve for time to get time = .1/.4 = 1/4 of an hour.
half of the remaining water in the bucket will be drained in a quarter of an hour.
Answer by josmiceli(19441)  (Show Source):
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