SOLUTION: To start the construction o a rest house. the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the shape of regula

Algebra ->  Triangles -> SOLUTION: To start the construction o a rest house. the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the shape of regula      Log On


   

Question 1013632: To start the construction o a rest house. the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the shape of regular pentagon. The desired area of the floor plan is 80 meter squared. Find the length of the string needed in the layout. Consider that 5% is accounted for tying.
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To start the construction o a rest house. the engineer advice his foreman to erect five pegs to establish the perimeter (outside) of the floor plan, which is in the shape of regular pentagon. The desired area of the floor plan is 80 meter squared. Find the length of the string needed in the layout. Consider that 5% is accounted for tying.
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Find the side of a regular pentagon with area = 80 sq meters
Area+=+ns%5E2%2Acot%28180%2Fn%29%2F4 where n = # of sides and s = side length
80+=+5s%5E2%2Acot%2836%29%2F4
s%5E2+=+80%2A4%2Atan%2836%29%2F5+=+64%2Atan%2836%29
s =~ 6.819 meters
P = 5s = 34.095 meters
+ 5% --> 35.8 meters