SOLUTION: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much

Algebra ->  Finance -> SOLUTION: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much      Log On


   



Question 1013590: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Call x the amount he invested at 2%. Thus he invested x+800 at 4%.
The setup looks like this then:
.02x + .04(x+800) = 92
.02x + .04x + 32 = 92
.06x = 60
x = $1000 at 2%
which means
800+x = $1800 at 4%