SOLUTION: If you don't mind helping me out with my homework: I would be very grateful! x² + bx + c = (x + p)(x + q), where pq = b and p + q = c. True False

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If you don't mind helping me out with my homework: I would be very grateful! x² + bx + c = (x + p)(x + q), where pq = b and p + q = c. True False       Log On


   



Question 1013563: If you don't mind helping me out with my homework: I would be very grateful!
x² + bx + c = (x + p)(x + q), where pq = b and p + q = c.

True

False

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
If you don't mind helping me out with my homework: I would be very grateful!
x² + bx + c = (x + p)(x + q), where pq = b and p + q = c.
True
False
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False.

The correct identities are pq = c and p + q = b.