Question 101350: 6r + 5= 8(r + 2) -2r
How do you solve this problem?
6r + 5 = 8r + 16 - 2r
6r + 5 = 6r + 16
0r = 11
r= 0 this is not correct though!
Answer by ckaeser(6)   (Show Source):
You can put this solution on YOUR website! 6r+5=8(r+2)-2r
Since r is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
8(r+2)-2r=6r+5
Multiply 8 by each term inside the parenthesis (r+2).
(8(r)+8(2))-2r=6r+5
Complete the multiplication of 8 by each term inside the parenthesis.
(8r+16)-2r=6r+5
Since 8r and -2r are like terms, add -2r to 8r to get 6r.
6r+16=6r+5
Since 6r contains the variable to solve for, move it to the left-hand side of the equation by subtracting 6r from both sides.
6r+16-6r=5
Since 6r and -6r are like terms, add -6r to 6r to get 0.
0+16=5
Combine all similar terms in the polynomial 6r-6r+16.
16=5
Since Since 16≠5, there are no solutions.
No Solution
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