SOLUTION: a picture frame has a perimeter of 62 inches. the difference between the length and twice the width is 1 inch. what are the length and width of the frame?

Algebra ->  Rectangles -> SOLUTION: a picture frame has a perimeter of 62 inches. the difference between the length and twice the width is 1 inch. what are the length and width of the frame?       Log On


   

Question 1013321: a picture frame has a perimeter of 62 inches. the difference between the length and twice the width is 1 inch. what are the length and width of the frame?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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L=length; W=width
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L-2W=1
L=2W+1
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P=2(L+W)
62in=2((2W+1)+W)
31in=3W+1
30in=3W
10in=W
ANSWER 1: The width is 10 inches.
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L=2W+1=2(10in)+1=20in+1in=21in
ANSWER 2: The length is 21 inches.
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CHECK:
P=2(L+W)
62in=2(21in+10in)
62in=2(31in)
62in=62in