SOLUTION: the area of master piston of a hydraulic press is 10cm^2 and the area of the slave piston is 1000cm^2 when an effort of 50n is exerted on the master piston calculate the: pressure

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Question 1013256: the area of master piston of a hydraulic press is 10cm^2 and the area of the slave piston is 1000cm^2 when an effort of 50n is exerted on the master piston calculate the: pressure in the hydraulic fluid , and the maximum weight the press can lift
Answer by ikleyn(52810) About Me  (Show Source):
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The area of master piston of a hydraulic press is 10 cm^2 and the area of the slave piston is 1000 cm^2.
When an effort of 50 n is exerted on the master piston calculate: the pressure in the hydraulic fluid, and the maximum weight the press can lift
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The pressure (in Pascals) in the hydraulic fluid is an effort (in newtons) divided by the area of master piston (m%5E2):

P = F%5B1%5D%2FS%5B1%5D = 50%2F0.001 = 50000 Pa.

This pressure is exerted on the slave piston surface area too.

Hence, the maximum weight the press can lift is the product of this pressure P by the area on the slave piston S%5B2%5D in m%5E2:

F%5B2%5D = P%2AS%5B2%5D = 50000*0.1 = 5000 newtons.

The general rule for a hydraulic press : the forces are proportional to areas: F%5B2%5D%2FF%5B1%5D = S%5B2%5D%2FS%5B1%5D,  or  F%5B1%5D%2FS%5B1%5D = F%5B2%5D%2FS%5B2%5D

Each side of the last proportion is the pressure of hydraulic liquid.

On hydrailc press see this article in Wikipedia.