SOLUTION: Solve log(3x+1) - log(2x+3) = log 2 by graphing. Then solve the equation by using the Exponential - Logarithmic Properties. Explain the result. Please include steps :D

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve log(3x+1) - log(2x+3) = log 2 by graphing. Then solve the equation by using the Exponential - Logarithmic Properties. Explain the result. Please include steps :D      Log On


   



Question 1013157: Solve log(3x+1) - log(2x+3) = log 2 by graphing. Then solve the equation by using the Exponential - Logarithmic Properties. Explain the result.
Please include steps :D

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
I cannot graph this here, but I can help you solve it...
log(3x+1) - log(2x+3) = log 2
log((3x+1)/(2x+3)) = log 2
(3x+1)/(2x+3) = 2
3x + 1 = 2(2x + 3)
3x + 1 = 4x + 6
x = -5
But there are no logs of negative numbers, so there is no solution...