SOLUTION: Hi! The problem is: An ice cream parlor makes $200. They sell cups of ice cream for $0.60 and cones for $2. How much cups of ice cream did they sell? How much cones of ice cream di

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Question 1013078: Hi! The problem is: An ice cream parlor makes $200. They sell cups of ice cream for $0.60 and cones for $2. How much cups of ice cream did they sell? How much cones of ice cream did they sell?
Thanks so much for your help!
I've tried to divide $200 by 0.60 but what about the cones?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = number of cups of ice cream sold
Let +b+ = number of cones sold
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(1) +.6a+%2B+2b+=+200+
(1) +6a+%2B+20b+=+2000+
(1) +3a+%2B+10b+=+1000+
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You need another equation to actually solve this.
You have 2 unknowns and only 1 equation
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+a+ has to be a multiple of +10+, since
that's the only way to end up with +0+ in the
units digit of +200+
So, there are many possible answers:
+3%2A10+%2B+10b+=+1000+
+3%2A20+%2B+10b+=+1000+
+3%2A30+%2B+10b+=+1000+
etc.
Find +b+ for each equation
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But the problem is still that you are missing data