SOLUTION: The right triangle has an area of 10 sq. cm. Find the length of its hypotenuse given two vertices A(3,8) and B(3,4).

Algebra ->  Surface-area -> SOLUTION: The right triangle has an area of 10 sq. cm. Find the length of its hypotenuse given two vertices A(3,8) and B(3,4).      Log On


   



Question 1013056: The right triangle has an area of 10 sq. cm. Find the length of its hypotenuse given two vertices A(3,8) and B(3,4).
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
You can try letting AB be one of the legs. Base OR height is AB, and the other leg is whatever length you need for the area to be specified, 10 sq cm.

Let k be the other leg.
%281%2F2%29%28AB%29k=10
%28k%2F2%29AB=10
k=20%2FAB
k=20%2Fsqrt%28%283-3%29%5E2%2B%288-4%29%5E2%29

k=20%2F4

k=5


AB found to be 4, and k found to be 5.
These are the triangle's dimensions, a RIGHT TRIANGLE.
Hypotenuse: sqrt%28%284%29%5E2%2B%285%29%5E2%29
highlight%28sqrt%2841%29%29--------the hypotenuse