SOLUTION: a ship leaves a port and sails for 4 hours on a course of 38� at 18 knots. Then the ship changes its course to 168� and sails for 6 hours at 16 knots. After the 10 hours (a) what i

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Question 1013019: a ship leaves a port and sails for 4 hours on a course of 38� at 18 knots. Then the ship changes its course to 168� and sails for 6 hours at 16 knots. After the 10 hours (a) what is the distance of the ship from the port and (b) what is the bearing from the port to the ship?
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
a ship leaves a port and sails for 4 hours on a course of 38� at 18 knots. Then the ship changes its course to 168� and sails for 6 hours at 16 knots. After the 10 hours (a) what is the distance of the ship from the port and (b) what is the bearing from the port to the ship?
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x-coordinate:: 4*18*cos(38) + 6*16*cos(168) = -37.17 knots
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y-coordinate:: 4*18 sin(38) + 6*16*sin(168) = 64.29 knots
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Distance = sqrt[37.17^2 + 64.29^2] = 74.26 knots
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Bearing:: arctan(64.29/-37.17) = 180-59.97 = 120.03 degrees
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Cheers,
Stan H.
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