SOLUTION: (mx+4)(2x-5) is simplified to 6x^2+23x-20 What is the value of m? I forget how to do this.

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Question 1012995: (mx+4)(2x-5) is simplified to 6x^2+23x-20
What is the value of m?
I forget how to do this.
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Foil out the first
2x^2m-5mx+8x-20=6x^2+23x-20
2x^2m-5mx=6x^2+15x
divide by x
2xm-5m=6x-15
m(2x-5)=6x-15
m=3
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Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

(mx+4)(2x-5) is simplified to 6x^2+23x-20
What is the value of m?
I forget how to do this. 
6x%5E2+%2B+23x+-+20 cannot be factored with integers, as there are no 2 integers than MULTIPLY to get - 120 (ac), and SUM to + 23 (b). 

In this case, highlight_green%28matrix%283%2C1%2Cm+=+0.730396696%2C%22OR%22%2Cm+=+-+4.5637%29%29