SOLUTION: Please help me solve this : In an geometric progression , b1=3 and b2=6 Calculate b2015

Algebra ->  Expressions-with-variables -> SOLUTION: Please help me solve this : In an geometric progression , b1=3 and b2=6 Calculate b2015      Log On


   

Question 1012978: Please help me solve this :
In an geometric progression , b1=3 and b2=6
Calculate b2015
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The general term will be cross%28b%5Bn%5D=3%5E%28n-1%29%29.
General term is 3%2A2%5E%28n-1%29

b%5B2015%5D=3%2A2%5E%282014%29=cross%288.3600140129806392468037591442514e%2B960%29
... is 5.6432919934120158375092217504285e+606

or about 5.64329%2A10%5E606



--
Corrected mistake