SOLUTION: : To complete a work 'A' takes 50% more time than 'B'. If together they take 18 days to complete the work, how much time will 'B' take to do it?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: : To complete a work 'A' takes 50% more time than 'B'. If together they take 18 days to complete the work, how much time will 'B' take to do it?       Log On


   



Question 1012955: : To complete a work 'A' takes 50% more time than 'B'. If together they take 18 days to complete the work, how much time will 'B' take to do it?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
To complete a work 'A' takes 50% more time than 'B'.
If together they take 18 days to complete the work, how much time will 'B' take to do it?
:
let b = time required by B to do the job
"To complete a work 'A' takes 50% more time than 'B'"; therefore
1.5b = Time required by A to do the job
:
Let the completed job = 1
Each will do a fraction of the job, the two fractions add up to 1
18%2F%281.5b%29 + 18%2Fb = 1
Get rid of the fractions, multiply equation by 3b
3b*18%2F%281.5b%29 + 3b*18%2Fb = 3b(1)
Cancel the denominators
2(18) + 3(18) = 3b
36 + 54 = 3b
90 = 3b
b = 90/3
b = 30 hrs required by B to do the job alone
:
:
Check this
18%2F%281.5%2A30%29 + 18%2F30 = 1
18%2F45 + 18%2F30 = 1
using a calc
.4 + .6 = 1