SOLUTION: Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they charged a total of 1850. What was the rate charged

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they charged a total of 1850. What was the rate charged       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1012932: Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they charged a total of 1850. What was the rate charged per hour by each mechanic if the sum of the two rates was 160 per hour?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
F=hourly rate for first mechanic; S=hourly rate for second mechanic
.
F+S=160
F=160-S
.
5F+15S=1850
5(160-S)+15S=1850
800-5S+15S=1850
10S=1050
S=105
ANSWER 1: The second mechanic charged 105 per hour.
.
F=160-F=160-105=55
ANSWER 2: The first mechanic charged 55 per hour.
.
CHECK:
5F+15S=1850
5(55)+15(105)=1850
275+1575=1850
1850=1850
.