SOLUTION: Please help me solve this : In an geometric progression , b1=3 and b2=6 Solve b2015
Algebra
->
Expressions-with-variables
-> SOLUTION: Please help me solve this : In an geometric progression , b1=3 and b2=6 Solve b2015
Log On
Algebra: Expressions involving variables, substitution
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Expressions-with-variables
Question 1012864
:
Please help me solve this :
In an geometric progression , b1=3 and b2=6
Solve b2015
Answer by
stanbon(75887)
(
Show Source
):
You can
put this solution on YOUR website!
Please help me solve this :
In an geometric progression , b1=3 and b2=6
--------
a = 3
ar = 6
---
ar/a = 6/3
r = 2
---------
Solve b2015 = ar^(2014) = 3*2^2014
-------------
Cheers,
Stan H.
------------