SOLUTION: If 1/(a-(-w))-(-1)/(b-(-w))-(-1)/(c -(-w))-(-1)/(d-(-w))=2w^2 and 1/(a-(-w^2))-(-1)/(b-(-w^2))-(-1)/(c-(-w^2))-(-1)/(d-(-w^2))=2w then prove that 1/(a-(-1))-(-1)/(b-(-1))-(-1)/(c-

Algebra ->  Square-cubic-other-roots -> SOLUTION: If 1/(a-(-w))-(-1)/(b-(-w))-(-1)/(c -(-w))-(-1)/(d-(-w))=2w^2 and 1/(a-(-w^2))-(-1)/(b-(-w^2))-(-1)/(c-(-w^2))-(-1)/(d-(-w^2))=2w then prove that 1/(a-(-1))-(-1)/(b-(-1))-(-1)/(c-      Log On


   



Question 1012813: If 1/(a-(-w))-(-1)/(b-(-w))-(-1)/(c -(-w))-(-1)/(d-(-w))=2w^2 and 1/(a-(-w^2))-(-1)/(b-(-w^2))-(-1)/(c-(-w^2))-(-1)/(d-(-w^2))=2w then prove that 1/(a-(-1))-(-1)/(b-(-1))-(-1)/(c-(-1))-(-1)/(d-(-1))=2
please ........please solve this question

Answer by ikleyn(52784) About Me  (Show Source):
You can put this solution on YOUR website!
.
Now your formulas look much better.

Thank you for following my instructions.

Now tell us please what is w in these formulas.

Comment from student: w, is cube root of unity in this question

OK, very good. 

So,  w = sqrt%281%29 = %28-1%2F2%29+%2B+i%2A%28sqrt%283%29%2F2%29  is this complex number.

Let me rewrite what is given and what you want to prove in an equivalent, but simpler form:

If 1%2F%28a%2Bw%29+%2B+1%2F%28b%2Bw%29+%2B+1%2F%28c%2Bw%29+%2B+1%2F%28d%2Bw%29 = 2w%5E2 (1) and 1%2F%28a%2Bw%5E2%29+%2B+1%2F%28b%2Bw%5E2%29+%2B+1%2F%28c%2Bw%5E2%29+%2B+1%2F%28d%2Bw%5E2%29 = 2w (2) then prove that 1%2F%28a%2B1%29+%2B+1%2F%28b%2B1%29+%2B+1%2F%28c%2B1%29+%2B+1%2F%28d%2B1%29 = 2.
Let us add the formulas (1) and (2) term-by-term. I will start with the pair of addends with the symbol "a", and will simplify it step by step: 1%2F%28a%2Bw%29 + 1%2F%28a%2Bw%5E2%29 = (write with the common denominator and then add the numerators. You will get) = %28%28a%2Bw%5E2%29+%2B+%28a%2Bw%29%29%2F%28%28a%2Bw%29%2A%28a%2Bw%5E2%29%29 = %282a+%2B+w+%2B+w%5E2%29%2F%28a%5E2+%2Baw+%2B+aw%5E2+%2B+w%5E3%29 = (now recall that w%5E3 = 1. So, replace w%5E3 by 1 in the last formula. You will get) = %282a+%2B+w+%2B+w%5E2%29%2F%281+%2B+a%5E2+%2B+a%28w+%2B+w%5E2%29%29 = (now use the fact that for your special number "w" there is the identity w+%2B+w%5E2 = -1. So, substitute it into the last formula. You will get) = %28-1%2B2a%29%2F%281+-+a+%2B+a%5E2%29. OK. It looks like I can not simplify it further. You can make this trick with every other pair of addends containing the symbols "b", "c" and "d". In this way you will obtain similar formulas. Now, when you add right sides of these long formulas, you will get 2w%5E2+%2B+2w%7D%7D%2C+which+is+%7B%7B%7B2%2A%28w+%2B+w%5E2%29. It equals -2 based on what was noted above. Finally, after adding these long formulas and simplifications, you get %281+-+2a%29%2F%281+-+a+%2B+a%5E2%29 + %281+-+2b%29%2F%281+-+b+%2B+b%5E2%29 + %281+-+2c%29%2F%281+-+c+%2B+c%5E2%29 + %281+-+2d%29%2F%281+-+d+%2B+d%5E2%29 = 2. It is not exactly what you requested. But it is what our mother-nature allows us to do.