SOLUTION: the second of two numbers is 3 times the first. Eight times the sum of first number and -2 is equal to the second number decreased by 11. find the numbers

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Question 1012651: the second of two numbers is 3 times the first. Eight times the sum of first number and -2 is equal to the second number decreased by 11. find the numbers
Found 2 solutions by josgarithmetic, fractalier:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Give the two numbers their variables.
m and n.


What does the description say?
system%28n=3m%2C8%28m%2B%28-2%29%29=n-11%29

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Call the first and second numbers, x and y. Then we can write
y = 3x and
8(x - 2) = y - 11
Now substitute the first eqn into the second and get
8(x - 2) = 3x - 11
8x - 16 = 3x - 11
5x = 5
x = 1
y = 3