SOLUTION: Simplify log8+log4-log2

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Question 1012540: Simplify log8+log4-log2
Found 2 solutions by fractalier, Alan3354:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
log8+log4-log2 = log(2^3) + log(2^2) - log(2) = 3log2 + 2log2 - log2 = 4log2

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify log8+log4-log2
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Adding logs --> multiply
Subtracting --> divide
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= log(8*4/2)
= log(16)