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| Question 101253:  Convert the rectangular point (-8,8sqrt3) to polar coordinates with r>0.
 Also give two additional ways to represent this point in polar coordinates
 for which r<0 and -2pi
*and* r>0 and -2pi
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Convert the rectangular point (-8,8sqrt3) to polar coordinates with r>0. r=sqrt(8^2+(8sqrt3)^2)= sqrt(256)= 16
 theta = tan^-1((8sqrt3)/-8)=tan^-1(-sqrt3)=120 degrees or (2/3)pi
 polar form: (16,(2/3)pi)
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 (-16,(5/3)pi)
 
 Also give two additional ways to represent this point in polar coordinates
 for which r<0 and -2pi
(-16,(-pi/3))
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 *and* r>0 and -2pi
(16,((-4/3)pi))
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 Cheers,
 Stan H.
 
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