SOLUTION: How to solve this problem Johnson family bought 4 adult tickets and 2 child tickets for a total of $37 to the movies. And the Gonzalez family bought 3 adult tickets and 4 c

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: How to solve this problem Johnson family bought 4 adult tickets and 2 child tickets for a total of $37 to the movies. And the Gonzalez family bought 3 adult tickets and 4 c      Log On


   



Question 1012491: How to solve this problem
Johnson family bought 4 adult tickets and 2 child tickets for a total of $37 to the movies. And the Gonzalez family bought 3 adult tickets and 4 child tickets for a total of $39. What is the price of each type of ticket(adult and child) at this movie theater

Answer by ikleyn(52794) About Me  (Show Source):
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How to solve this problem
Johnson family bought 4 adult tickets and 2 child tickets for a total of $37 to the movies. And the Gonzalez family bought 3 adult tickets and 4 child tickets for a total of $39. What is the price of each type of ticket(adult and child) at this movie theater
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From the condition, you have this system of two equations:

4a + 2c = 37,   (1)
3a + 4c = 39.   (2)

where unknowns a and c are the ticket costs for adult and children respectively.

To solve it, multiply equation (1) by (-2) (both sides) and then add to the equation (2). You will get

-8a + 3a = -2*37 + 39,   or

-5a = -35.

Therefore, a = %28-35%29%2F%28-5%29 = 7 dollars is the price for the adult ticket.

Now try yourself to complete the solution.