You can put this solution on YOUR website! the product of 3 consecutive even natural numbers divided by their sum is 64. what is the middle number?
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1st:: 2x-2
2nd:: 2x
3rd:: 2x+2
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Equation:
2x(4x^2-4)/6x = 64
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4x^2-4 = 3*64
x^2 -1 = 3*16
x^2 = 49
x = 7 or x = -7
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1st:: 2x-2 = 12
2nd:: 14
3rd:: 16
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OR
1st:: -16
2nd:: -14
3rd:: -12
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Cheers,
Stan H.
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You can put this solution on YOUR website! .
the product of 3 consecutive even natural numbers divided by their sum is 64. what is the middle number?
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Let x be that middle number.
Then the three numbers are (x-2), x, and (x+2).
Their product is P = (x-2)*x*(x+2) = x*(x^2 - 4).
Their sum is S = (x-2) + x + (x+2) = 3x.
The equation is
= 64, or = 64, or = 64.
= 64*3 = 192, = 192 + 4 = 196, x = +/-14.
Since the condition talks about natural numbers, only positive value is the solution.
Answer. x = 14.
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