SOLUTION: Factor the following trinomial completely x^2-11x-60 thank you for any help i can help

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Question 101242: Factor the following trinomial completely

x^2-11x-60
thank you for any help i can help

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression x%5E2-11x-60, we can see that the first coefficient is 1, the second coefficient is -11, and the last term is -60.



Now multiply the first coefficient 1 by the last term -60 to get %281%29%28-60%29=-60.



Now the question is: what two whole numbers multiply to -60 (the previous product) and add to the second coefficient -11?



To find these two numbers, we need to list all of the factors of -60 (the previous product).



Factors of -60:

1,2,3,4,5,6,10,12,15,20,30,60

-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -60.

1*(-60) = -60
2*(-30) = -60
3*(-20) = -60
4*(-15) = -60
5*(-12) = -60
6*(-10) = -60
(-1)*(60) = -60
(-2)*(30) = -60
(-3)*(20) = -60
(-4)*(15) = -60
(-5)*(12) = -60
(-6)*(10) = -60


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -11:



First NumberSecond NumberSum
1-601+(-60)=-59
2-302+(-30)=-28
3-203+(-20)=-17
4-154+(-15)=-11
5-125+(-12)=-7
6-106+(-10)=-4
-160-1+60=59
-230-2+30=28
-320-3+20=17
-415-4+15=11
-512-5+12=7
-610-6+10=4




From the table, we can see that the two numbers 4 and -15 add to -11 (the middle coefficient).



So the two numbers 4 and -15 both multiply to -60 and add to -11



Now replace the middle term -11x with 4x-15x. Remember, 4 and -15 add to -11. So this shows us that 4x-15x=-11x.



x%5E2%2Bhighlight%284x-15x%29-60 Replace the second term -11x with 4x-15x.



%28x%5E2%2B4x%29%2B%28-15x-60%29 Group the terms into two pairs.



x%28x%2B4%29%2B%28-15x-60%29 Factor out the GCF x from the first group.



x%28x%2B4%29-15%28x%2B4%29 Factor out 15 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x-15%29%28x%2B4%29 Combine like terms. Or factor out the common term x%2B4



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Answer:



So x%5E2-11%2Ax-60 factors to %28x-15%29%28x%2B4%29.



In other words, x%5E2-11%2Ax-60=%28x-15%29%28x%2B4%29.



Note: you can check the answer by expanding %28x-15%29%28x%2B4%29 to get x%5E2-11%2Ax-60 or by graphing the original expression and the answer (the two graphs should be identical).