SOLUTION: Verify that the equation is an identity
{{{(cot^2(x) - tan^2(x)) / (cot^""(x)^"" + tan^""(x))^2}}}{{{""=""}}}{{{2cos^2(x)-1}}}
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-> SOLUTION: Verify that the equation is an identity
{{{(cot^2(x) - tan^2(x)) / (cot^""(x)^"" + tan^""(x))^2}}}{{{""=""}}}{{{2cos^2(x)-1}}}
Log On
Work with the left side. Factor the numerator as the difference
of two squares.
Write the denominator as the product of
two equal factors:
Cancel:
Use the quotient identities to change everything to sines
and cosines:
Multiply top and bottom by LCD = sin(x)cos(x)
Use the Pythagorean identity to replace the bottom by 1:
Use the Pythagorean identity to change the sin2(x)
Edwin