SOLUTION: Liz is 2.5 times her sons present age. Eight years ago, the total of their ages was 47. How old is each person now?

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Question 1012285: Liz is 2.5 times her sons present age. Eight years ago, the total of their ages was 47. How old is each person now?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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S=son's age; L=Liz's age=2.5S
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(S-8)+(L-8)=47
S+L-16=47
S+L=63
The sum of their ages now is 63.
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S+L=63
S+2.5S=63
3.5S=63
S=18
ANSWER 1: Son is 18 years old.
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L=2.5S=2.5(18)=45
Liz is 45 years old.
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CHECK:
(S-8)+(L-8)=47
(18-8)+45-8)=47
10+37=47
47=47