SOLUTION: What is y-3=3(x+1) in standard form of a parallel line that passes through (0,-3)

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Question 1012251: What is y-3=3(x+1) in standard form of a parallel line that passes through (0,-3)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the question this way:
What is the equation in standard form for the line parallel to y-3=3(x+1) that passes through (0,-3) ?

y=3x%2Bb
y-3x=b
but you are already given the expected b, the y-intercept.
y=3x-3
-3x%2By=-3
highlight%283x-y=3%29

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

What is y-3=3(x+1) in standard form of a parallel line that passes through (0,-3)
The equation's slope  = 3; and the point (0, - 3) is the y-intercept

Therefore, we get: y = 3x - 3

highlight_green%283x+-+y+=+3%29 ------- Converting to standard form