SOLUTION: What is the equation of the line which: a) passes through the point (2, -7) and is parallel to y = 2; and b) passes through the point (-1, 2), and is parallel to the line x = 1

Algebra ->  Length-and-distance -> SOLUTION: What is the equation of the line which: a) passes through the point (2, -7) and is parallel to y = 2; and b) passes through the point (-1, 2), and is parallel to the line x = 1      Log On


   



Question 1012231: What is the equation of the line which: a) passes through the point (2, -7) and is parallel to y = 2; and b) passes through the point (-1, 2), and is parallel to the line x = 1
Answer by ValorousDawn(53) About Me  (Show Source):
You can put this solution on YOUR website!
If a line is parallel to a line that is in the form y=k, with k a constant, that latter line will be in the same form. The y value is always constant in that function, therefore, if it passes through the point (2, -7), it has to have the same y value for that point, namely, -7. Therefore, our line is given by y=-7.
The same argument applies here, but for the x value instead. If it has to cross through the point (-1, 2), and the x values are constant, it must have the same x value of that function of -1. As such, our function is x=-1