Question 1012045: The 250 soldiers in a camp had enough food for forty days, After 10 days, 50 soldiers joined them. For how long will the remaining food last them? Solve using variation.
Found 2 solutions by ValorousDawn, MathTherapy:
Answer by ValorousDawn(53)   (Show Source):
You can put this solution on YOUR website! I don't even think variation is a legitimate way to solve this problem but here's something.
Lets say each soldier eats 1 food unit every day. Forty days for 250 soldiers is 10,000 food units. After 10 days, they are down to 10,000-250*10=8,750. If there are now  , they then subsequently will eat 300 food units a day. They will have food for  days. If you must round, you'd round down, for 29 days.
Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
The 250 soldiers in a camp had enough food for forty days, After 10 days, 50 soldiers joined them. For how long will the remaining food last them? Solve using variation.
Let S be number of soldiers, k = constant of variation, j = amount of food, and T = time
k = 250(40), or 10,000
Let fraction consumed after 10 days, be j
j, or fraction consumed after 10 days =  , or 
With of food consumed  remains, and 300 (250 + 50) soldiers are in camp
300T = 7,500 ------- Cross-multiplying
T, or time the remaining of food will last =  , or  days
|
|
|
