SOLUTION: a.(1-tan^2u)/(1+tan^2u)=cos(2u)
I think this is a half angle identity?verify the identity.
b. compare the graphs of y1=(1-tan^2u)/(1+tan^2u) and y2=cos(2u)
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-> SOLUTION: a.(1-tan^2u)/(1+tan^2u)=cos(2u)
I think this is a half angle identity?verify the identity.
b. compare the graphs of y1=(1-tan^2u)/(1+tan^2u) and y2=cos(2u)
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Question 101196: a.(1-tan^2u)/(1+tan^2u)=cos(2u)
I think this is a half angle identity?verify the identity.
b. compare the graphs of y1=(1-tan^2u)/(1+tan^2u) and y2=cos(2u) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! verify the identity.
a.(1-tan^2u)/(1+tan^2u)=cos(2u)
(1-tan^2u)/sec^2u = cos^2u-sin^2u
[1/sec^2u] - [tan^2u/sec^2u] = cos^2u-sin^2u
cos^2u - sin^2u = cos^2u - sin^2u
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b. compare the graphs of y1=(1-tan^2u)/(1+tan^2u) and y2=cos(2u)
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Can't do that on this site.
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Cheers,
Stan H.
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