SOLUTION: Triangle TJK is a 45 degree-45 degree-90 degree triangle with right angle at J. What are the coordinates of T in Quadrant II For J(-2,-3) and K(3,-3).

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Question 1011755: Triangle TJK is a 45 degree-45 degree-90 degree triangle with right angle at J. What are the coordinates of T in Quadrant II For J(-2,-3) and K(3,-3).
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If you plot the 2 points, it's obvious T is (-2,2).

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The side JT is perpendicular to the
side JK.
Find the slope of JK:
J(-2,-3) and K(3,-3)
+m%5B1%5D+=+%28+-3+-%28-3%29+%29+%2F+%28+3+-%28-2%29+%29+
+m%5B1%5D+=+0+
Zero slope is a horizontal line, so any
line perpendicular to it is a vertical line
-----------------
The side JT goes through J( -2,-3 ), so
it's equation is +x+=+-2+
------------------------
The length of horizontal line JK is:
+d+=+sqrt%28+%28+3+-%28-2%29%29%5E2+%2B+%28+-3+-%28-3%29+%29%5E2+%29+
+d+=+sqrt%28+5%5E2+%2B+0%5E2+%29+
+d+=+sqrt%28+25+%29+
+d+=+5+
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Since it's a 45-45-90 triangle, side JT also
is +5+ units long.
It's a vertical line and the x-coordinate is +x+=+-2+
Point T is:
T( -2, 5 )
Note this is in quadrant 2 also