Question 1011722: 14. If calls to your cell phone are a Poisson process with a constant rate l=2 calls per hour, what’s the probability that, if you forget to turn your phone off in a 1.5 hour movie, your phone rings during that time? How many phone calls do you expect to get during the movie?
Answer by mathmate(429) (Show Source):
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Question:
If calls to your cell phone are a Poisson process with a constant rate l=2 calls per hour, what’s the probability that, if you forget to turn your phone off in a 1.5 hour movie, your phone rings during that time? How many phone calls do you expect to get during the movie?
Solution:
Given Poisson processes.
mean=λ=2 (per hour)
For a duration of 1.5 hours, mean = 3
P(not ring during 1.5 hours)
=P(0;3)=0.049787 (from tables of Poisson distribution)
Expected number of calls = mean = 3
Reference:
Poisson tables
http://www.dtic.upf.edu/~jblat/material/pipe/poisson_distribution.pdf
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