Question 1011676: Jeff has some coins. He can put the same number of coins into each of 9 bags, with no coins left over. He can put the same number of coins into each of 6 bags, with no coins left over. He can put the same number of coins into each of 5 bags, with 2 coins left over. What is the least number of coins that Jeff could have ?
This is what I did: LCM for 9 and 6 is 18. It is a multiple of 9 and 6. But when divided by 5, the remainder is 3 NOT 2.
PLEASE HELP !!!
Answer by ikleyn(52803)   (Show Source):
You can put this solution on YOUR website! .
Jeff has some coins. He can put the same number of coins into each of 9 bags, with no coins left over. He can put the same number of coins into each of 6 bags, with no coins left over. He can put the same number of coins into each of 5 bags, with 2 coins left over. What is the least number of coins that Jeff could have ?
This is what I did: LCM for 9 and 6 is 18. It is a multiple of 9 and 6. But when divided by 5, the remainder is 3 NOT 2.
PLEASE HELP !!!
-------------------------------------------------------------------
Try 72.
|
|
|
