SOLUTION: sin^-1 (3÷5) + sin^-1 (5÷13) = sin^-1 (56÷65)

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Question 1011508: sin^-1 (3÷5) + sin^-1 (5÷13) = sin^-1 (56÷65)
Answer by ikleyn(52869) About Me  (Show Source):
You can put this solution on YOUR website!
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sin^-1 (3÷5) + sin^-1 (5÷13) = sin^-1 (56÷65)
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Thus we need to prove that  arcsin%283%2F5%29 + arcsin%285%2F13%29 = arcsin%2856%2F65%29.

Proof

Let alpha = arcsin%283%2F5%29 and beta = arcsin%285%2F13%29.

Thus sin%28alpha%29 = 3%2F5 and alpha is in Quadrant 1;   sin%28beta%29 = 5%2F13 and beta is in Quadrant 1 also.

We need to prove that sin%28alpha+%2B+beta%29 = 56%2F65  and  alpha + beta is in Quadrant 1.

Since sin%28alpha%29 = 3%2F5, you have cos%28alpha%29 = sqrt%281+-+%283%2F5%29%5E2%29 = 4%2F5        (make all intermediate calculations yourself)

Since sin%28beta%29 = 5%2F13, you have cos%28beta%29 = sqrt%281+-+%285%2F13%29%5E2%29 = 12%2F13    (make all intermediate calculations yourself)

Now apply the formula for sin%28alpha%2Bbeta%29:

sin%28alpha+%2B+beta%29 = sin%28alpha%29%2Acos%28beta%29+%2B+cos%28alpha%29%2Asin%28beta%29 = %283%2F5%29%2A%2812%2F13%29+%2B+%284%2F5%29%2A%285%2F13%29 = %2836%2B20%29%2F%285%2A13%29 = 56%2F65.   

Thus the first half of the statement is proved.

Next calculate cos%28alpha%2Bbeta%29:

cos%28alpha+%2B+beta%29 = cos%28alpha%29%2Acos%28beta%29+-+sin%28alpha%29%2Asin%28beta%29 = %284%2F5%29%2A%2812%2F13%29+-+%283%2F5%29%2A%285%2F13%29 = %2848-15%29%2F%285%2A13%29 = 33%2F65.

Since cos%28alpha+%2B+beta%29 > 0, alpha+%2B+beta is in the quadrant 1.

The proof is completed.